# How do you condense #log (3x+1)=2#?

##### 2 Answers

Jan 13, 2016

#### Explanation:

This can be rewritten as

#log_10(3x+1)=2#

To undo the logarithm with base

#color(red)(cancel(color(black)(10^(log_10))))""^((3x+1))=10^2#

#3x+1=100#

#3x=99#

#x=33#

Jan 13, 2016

Just another way of writing exactly the same thing!

#### Explanation:

Given:

2 is the index that 10 has to be raised to give 3x+1. So we have: